How many moles of formic acid are formed in t | vedclass

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(C) The reaction of glucose $(CH_2OH(CHOH)_4CHO)$ with periodic acid $(HIO_4)$ involves the oxidative cleavage of all $C-C$ bonds between adjacent hyd

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(C) The reaction of glucose $(CH_2OH(CHOH)_4CHO)$ with periodic acid $(HIO_4)$ involves the oxidative cleavage of all $C-C$ bonds between adjacent hydroxyl groups. For glucose,the reaction is: $CH_2OH(CHOH)_4CHO + 5HIO_4 \rightarrow 5HCOOH + HCHO + 5HIO_3$. In this reaction,the aldehyde group and the four secondary alcohol groups are oxidized to $5$ moles of formic acid $(HCOOH)$,while the terminal primary alcohol group is oxidized to $1$ mole of formaldehyde $(HCHO)$. Therefore,$5$ moles of formic acid are formed.

How many moles of formic acid are formed in the given reaction?

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